★★★ Correct answer to the question: Using the equation, c5h12 + 8o2 imported asset 5co2 + 6h2o, if an excess of pentane (c5h12) were supplied, but only 4 moles of oxygen were available, how many moles of water would be produced? C5H12 + 8O2 → 5CO2 + 6H2O 2 See answers sdmatera sdmatera We can first rule out choices B and D because in decomposition reactions, one reactant is decomposed or broken up to form two or more products. 0 0 Comment. Fe2O3+3CO=2Fe+3CO2 How many moles of iron are produced from the reaction of 10 mol Fe2O3 and … 22.05 = 22.1 sig fig 0 0; Pat. 1. expected yield. Roger the Mole. What is the oxidizing agent when iron rusts? FREE Expert Solution Show answer. Relevance. Lv 7. Explanation: A. Limiting Reactant. C 5 H 12 + 8O 2 → 6H 2 O + 5CO 2. C5H12 + 8O2 --> 5CO2 + 6H2O. Then you add in the remaining oxygens. can you please please help me … 9 moles of reactants chemically change into 11 moles of products. Chemistry, 21.06.2019 20:20, mgavyn1052. 26 g. If 58 moles of NH3 are combined with 32 moles of sulfuric acid, what is the limiting reactant and how much of the excess reactant is left over? C5H12 + 8O2 —-> 5CO2 + 6H2O Firstly, you have pentane, and that’s being combusted so it won’t change. Using the equation, C5H12 + 8O2 Imported Asset 5CO2 + 6H2O, if an excess of pentane (C5H12) were supplied, but only 4 moles of oxygen were available, how many moles of water would be produced? The equation for the reaction is: SiO2+4HF=SiF4+2H2O . 4.41 mols C5H12 x (5 mols CO2/1 mol C5H12) = 4.41 x 5/1 = ? 0 0; DrBob222. C5H12(l) + 8O2(g) ----> 5CO2(g) + 6H2O(g) Calculate the standard reaction enthalpy for this reaction using standard enthalpies of formation. Chemistry. so, to balance the 16 oxygen molecules on the product side, you use 8 O2 molecules. Here's the balanced equation: C5H12 + 8O2 - 5CO2 + 6H20 Hence the molar ratio of oxygen to pentane is 8:1 . Similar Questions. Use the coefficients in the b balanced equation to convert anything to anything. +3. 85% (69 ratings) FREE Expert Solution. Answer Save. a) Write a balanced chemical equation for the combustion of pentane. 4 NH3 + 5 O2 → 4 NO + 6 H2O (80.0 g O2) / (31.99886 g O2/mol) = 2.5001 mol O2 (70.0 g NH3) / (17.03056 g NH3/mol) = 4.1103 mol NH3. Only authorized users can leave an answer! ____ —> Li2O. the formula above is a balanced combustion reaction for the reaction between C5H12 and O2. c) How many grams of water is formed at the end of the reaction Thus the equation is balanced as follow: There are 2 atoms of O on the left side and 1 atom on the right side. Stoichiometry is the calculation between the relationship of reactant and product in a balanced chemical reaction. Relevance. What is the maximum amount of product that should be produced from a given amount of reactant? So there has to be 5 carbons and then 6 hydrogens (12/2 =6) . have fun :) 1 0. duca. Roger the Mole. C5H12 + 8O2 → 6H2O + 5CO2. 4 NH3 + 5 O2 → 4 NO + 6 H2O (80.0 g O2) / (31.99886 g O2/mol) = 2.5001 mol O2 (70.0 g NH3) / (17.03056 g NH3/mol) = 4.1103 mol NH3. Balance the following unbalanced equation and determine how many moles of \(\ce{H2O}\) are produced when 1.65 mol of NH 3 react: \[\ce{NH3 + O2 → N2 + H2O} \nonumber\] Answer a 0.391 mol … Can't find the answer? Chemistry what is the 1. chemical equation 2. complete ionic equation 3. net ionic equation include phase of … 9 grams of reactants chemically changed into 11 grams products c. 9 litters of reactants chemically changed into 11 liters of products d. 9 atoms of reactants chemically change into 11 atoms of products. When an amount of pentane and an amount of oxygen are mixed in a particular experiment 100. grams of carbon dioxide are produced. If 4.36 moles of C5H12 reacts with excess O2, how many moles of CO2 will be produced in the following combustion reaction? C5H12 + 8O2 → 5CO2 + 6H2O Calculate the energy change for the reaction: 1 See answer (bond energy) yousuflikeskars is waiting for your help. Relevance. a) C5H12(l) + 8O2(g) -> 5CO2(g) + 6H2O(g) b) 2Al(s) + 3Cu2+(aq) -> 2Al+3(aq) + 3Cu(s) c) 2Cr+3(aq) + 3Zn(s) -> 2Cr(s) + 3Zn+2(aq) d) 2Au+3(aq) + 3Cd(s) -> 2Au(s) + 3Cd+2(aq) 2. To … How many moles of O2 needed to produce 11.5 grams of CO2? C5H12+8O2->5CO2+6H2O. Answer Save. How many grams of H2O will you make? 2.5001 moles of O2 would react … What is the reducing agent? Related questions. Then we need to determine which choice, A or C, is correctly balanced. Answers. And your good. Thus the equation is given below: Li + O2 —> Li2O. Given the following balanced chemical equation: \[\ce{C5H12 + 8O2 → 5CO2 + 6H2O} \nonumber\], How many moles of \(\ce{H2O}\) can be formed if 0.0652 mol of \(\ce{C_{5}H_{12}}\) were to react? C5H12 + 8O2 → 5CO2 + 6H2O In above reaction, 1 mole of C5H12 reacts with 8 moles of oxygen to give 6 moles of water. Favourite answer. Answer. Select one: a. The rate of a chemical reaction is defined as the rate of change in concentration of a reactant or product divided by its coefficient from the balanced equation. Thus, 4 moles of oxygen will react with 0.5 mole of C5H12, to generate 3 moles of H2O. Lv 7. 92.8 g of CO2 . If 7.65 moles of C 5 H 12 reacts with excess O 2, how many moles of CO 2 will be produced in the following combustion reaction? Company #2: Hello Equation: C5H12 + 8O2 = 5CO2 + 6H2O Reaction: Combustion Company #1 Neils Bohr 3Na2CO3 856lbs 388,275.07g 1320.62 Company #1 Neils Bohr 2AlPO4 165lbs 74,842.74 306.86 Company #2 Hello C5H12 663lbs 300,731.74 4,166.99 Company #2 Hello 8O2 728lbs 330,215.25 1,289.90 Limiting reactant: “Neils Bohr” 2AlPO4 Excess amount: 860.1 Limiting reactant: … 1. FeS 2HCl FeCl2 H2S 8 copperII hydroxide acetic acid Copper2 Acetate water CuOH2 from SCIENCE CHE121 at Truett McConnell University C5H12 + 8O2 -----> 6H2O + 5CO2. 8 years ago. On the product side you have CO2 and H2O. 164 g. What mass of SiF4 could be produced by the reaction of 15 g of SiO2 with an excess of HF? MXrox! Asked: How many moles of H2O can be formed with 0.200 mol of C5H12. C5H12 + 8O2 10CO2 + 6H2O What is the mole ratio of oxygen to pentane? A negative sign is used with rates of change of reactants and a positive sign with those of products, ensuring that the reaction rate is always a positive quantity. Chemistry When a mixture of 13.0 g of acetylene (C2H2) and 13.0 g of oxygen (O2) is ignited, the resultant combustion reaction produces CO2 and H2O. Grace Nov 9, 2015 #C_5H_12 + 8# #O_2 -> 6# #H_2O + 5# #CO_2# Answer link. C5H12 (l) + 8O2 (g)~ 5CO2 (g) + 6H2O (g) a. Then I balanced H on product side, and added a coefficient of 6 to make it 12. To produce 4 moles of water, 4/6 moles of pentane must react. Choice A is incorrectly balanced because there … This made Hydrogen balance also, and it gave oxygen a 16 on product side. You cant reduce it because 5, 6, and 8 aren't factorable together. Limiting reagent: Compound: Coefficient: Molar Mass: Moles: Weight: C 5 H 12: 5: 72.14878: O 2: 25: 31.9988: CO 2: 25: 44.0095: H 20: 3: 20.1588: Units: molar mass - g/mol, weight - g. Please tell about this free chemistry software to your friends! 85% (69 ratings) Problem Details . you initially had 16 oxygen molecules on the reactant side. 9 moles of reactants chemically change into 11 moles of products b. Using the equation, c5h12 8o2 arrow 5co2 6h2o, if 108 g of water are produced, how many grams of oxygen were consumed? C5H12 + 8O2 --> 5CO2 + 6H2O You start with 150.0 g of pentane and 500.0 L of O2. Re: Enthalpies of Formation and delta H. Post by Chem_Mod » Wed Jan 22, 2014 5:03 am . ,v wkh surfhvv ri exuqlqj wkh frpelqdwlrq ri dq rujdqlf vxevwdqfh zlwk r[\jhq wr surgxfh d iodph :khq dq rujdqlf frpsrxqg exuqv lq r[\jhq wkh fduerq uhdfwv zlwk r[\jhq wr irup &2 C5H12 + 8O2 --> 5CO2 + 6H2O You start with 150.0 g of pentane and 500.0 L of O2. Respond to this Question. How many grams of H2O will you make? C 5 H 12 + 8O2 → 6H 2 O + 5CO 2. Explanation: #C_5H_12+8O_2 rarr 6H_2O + 5CO_2# From the equation, we see that 1 mole of #C_5H_12# reacts with excess of #O_2# to produce #5# moles of #CO_2.# So, #4.36# moles of #C_5H_12 … It can be balance by putting 2 in front of Li2O as shown below: Li + O2 —> 2Li2O. Chemistry, 21.06.2019 22:30, david2767. a. 1. FREE Expert Solution Show answer. Mole Ratio. So all that was left was to add 8 in front of O2 on reactant side. C5H12 + 8O2 —> 5CO2 + 6H2O. 1:6 6:8 8:1 10:8 . - edu-answer.com Solved: You start with 150.0 g of pentane and 500.0 L of O2. steve_geo1. If 5.93 moles of C 5 H 12 reacts with excess O 2, how many moles of CO 2 will be produced in the following combustion reaction? Notice how there’s only one species with carbon and one with hydrogen on the product side. First Name. 1 Answer Candy Mar 20, 2018 #21.80# moles. Answers: 1 Get Other questions on the subject: Chemistry. The reactants are Li and O2. Aug 4, 2016 . 8 years ago. Answer Save. How many grams of O2 are required to burn 46.0 grams of C5H12? C5H12+8O2 --> 6H2O+5CO2 0 0 418; Lisa. 2 Answers. Log in or register to post comments; Similar Questions. a. The equation is not balanced properly. 2 Answers. Answers: 2 Show answers Other questions on the subject: Chemistry. Learn this topic by watching Stoichiometry Concept Videos. for the given equation C5H12+8O2->5CO2+6H2O: if the reactant C5H12 and O2 are having 2 moles and 8 moles initially a) Which is Excess reactant? What is the ratio between the coefficients of any two substances in a balanced equation? b) which is limiting reagent? 0. the balanced … C5H12 + 8O2 ----> 5CO2 + 6H2O. 2 Answers. How many grams of H2O will you make? Given: C5H12+8O2→5CO2+6H2O 0.200 mol C5H12. 90% (366 ratings) Problem Details. Add your answer and earn points. Learn this topic by watching Stoichiometry Concept Videos. (The standard enthalpy of formation of liquid pentane is -146.8 KJ/mol.) Therefore, mass of pentane needed= 4/6mol … C5H12(g)+8O2(g)→5CO2(g)+6H2O(g) Calculate the mass of CO2 that can be produced if the reaction of 38.5 g of pentane and sufficient oxygen has a 58.0 % yield. Choices B and D are incorrect because they both have two reactants. it's easiest to leave the oxygen last as it is the only element that is not part of a compound element. Chemistry. 2 Answers. When pentane, C5H12, is combusted in air, the products are carbon dioxide and water. Chem_Mod Posts: 19379 Joined: Thu Aug 04, 2011 8:53 pm Has upvoted: 872 times. Sep 25, 2013 . 2.5001 moles of O2 would react … Sep 25, 2013 . c. how many grams of CO2 are formed if 44.5 g of C5H12 is mixed with 108 g of O2? C5H12+8O2=5CO2+ 6H2O. I have the answers but need help on how to work the problems out please. A reaction that produces iron metal from iron ore is shown below. Now you do it with C6H14 . Law of conservation of mass is discussed where the total mass of the reactant and the total mass of the product is conserved. Identify which reactant is reduced and which is oxidized in each of the following reactions.? Answered by frazc. 9 years ago. Question #fee47 Question #c5c15 Question #19eb9 Question #e2ea2 Question #bc751 Question #e2ea6 Question … Answers (2) Zackary Willis 3 November, 15:12. 8 moles c. 12 moles d. 16 moles Question 2 Using the equation, 4Fe + 3O2 2Fe2O3, if 6 moles of oxygen and an excess of iron were available, how many moles of iron (III) … How many ml of 6.00 m naoh is needed to prepare 250 ml of 0.600 m naoh? Your Response. Question 1 Using the equation, C5H12 + 8O2 5CO2 + 6H2O, if 2 moles of pentane (C5H12) were supplied, and an unlimited amount of oxygen were available, how many moles of water would be produced? Answer Save. Relevance. Favorite Answer. C5H12 + 8O2 -----> 5CO2 + 6H20 1C5H12 + 8O2 --> 5CO2 + 6H2O. 6 moles b. C5H12 + 8O2 → 6H2O + 5CO2. 90% (366 ratings) FREE Expert Solution. Favourite answer. Calculate the molarity of the solution. 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